Tính các tổng sau (1 - 2x) / 6x^3y + (3 + 2x) / 6x^3y + (2x - 4) / 6x^3y
Tính các tổng sau:
\(\frac{{1 - 2x}}{{6{x^3}y}} + \frac{{3 + 2x}}{{6{x^3}y}} + \frac{{2x - 4}}{{6{x^3}y}}\).
\(\frac{{1 - 2x}}{{6{x^3}y}} + \frac{{3 + 2x}}{{6{x^3}y}} + \frac{{2x - 4}}{{6{x^3}y}}\)
=\(\frac{{1 - 2x + 3 + 2x + 2x - 4}}{{6{x^3}y}}\)
=\(\frac{{2x}}{{6{x^3}y}} = \frac{1}{{3{x^2}y}}\).