log2 5 = a. Tính log4 1250 theo a A. log4 1250 = 2(1 + 4a) B. log4 1250 = 2(1 + 4a)
\({\log _2}5 = a\) . Tính \({\log _4}1250\) theo a?
A. \({\log _4}1250 = 2\left( {1 + 4a} \right)\)
B. \({\log _4}1250 = 2\left( {1 + 4a} \right)\)
C. \({\log _4}1250 = 2\left( {1 - 4a} \right)\)
D. \({\log _4}1250 = \frac{{1 + 4a}}{2}\)