Tìm x, biết:

a) (x – 2)(x – 4) = 0

b) x²(x – 3) = 0

a) (x – 2)(x – 4) = 0

TH1: x – 2 = 0

x = 0 + 2

x = 2

TH2: x – 4 = 0

x = 0 + 4

x = 4

Vậy \[x = \left\{ {2;4} \right\}\]

b) x²(x – 3) = 0

TH1: x² = 0

x = 0

TH2: x – 3 = 0

x = 0 + 3

x = 3

Vậy x ∈ {0; 3}.