Tìm x, biết: 4x^2 - 25 - (2x - 5)(2x + 7) = 0
Tìm x, biết: 4x2 – 25 – (2x – 5)(2x + 7) = 0.
4x2 – 25 – (2x – 5)(2x + 7) = 0
\( \Leftrightarrow \)[(2x)2 – 52] – (2x – 5)(2x + 7) = 0
\( \Leftrightarrow \)(2x – 5)(2x + 5) – (2x – 5)(2x + 7) = 0
\( \Leftrightarrow \)(2x – 5)(2x + 5 – 2x – 7) = 0
\( \Leftrightarrow \)(2x – 5)(−2) = 0
\( \Leftrightarrow \)2x – 5 = 0
\( \Leftrightarrow x = \frac{5}{2}\).
Vậy \(x = \frac{5}{2}\).