Tìm x, biết: 1/4x^2 - (1/2x - 4) 1/2 x = -14
Tìm x, biết: \[\frac{1}{4}{x^2} - \left( {\frac{1}{2}x - 4} \right)\frac{1}{2}x = - 14\].
\(\frac{1}{4}{x^2} - \left( {\frac{1}{2}x - 4} \right)\frac{1}{2}x = - 14\)
\(\frac{1}{4}{x^2} - \left( {\frac{1}{4}{x^2} - 2x} \right) = - 14\)
\(\frac{1}{4}{x^2} - \frac{1}{4}{x^2} + 2x = - 14\)
2x = −14
x = − 7
Vậy x = − 7.