Giải các phương trình sau:

\(\cos \left( {\frac{{3x}}{2} + \frac{\pi }{4}} \right) = \frac{1}{2}\);

\(\cos \left( {\frac{{3x}}{2} + \frac{\pi }{4}} \right) = \frac{1}{2}\)

\( \Leftrightarrow \cos \left( {\frac{{3x}}{2} + \frac{\pi }{4}} \right) = \cos \frac{\pi }{3}\)

\( \Leftrightarrow \left[ \begin{array}{l}\frac{{3x}}{2} + \frac{\pi }{4} = \frac{\pi }{3} + k2\pi \\\frac{{3x}}{2} + \frac{\pi }{4} = - \frac{\pi }{3} + k2\pi \end{array} \right.\)\( \Leftrightarrow \left[ \begin{array}{l}\frac{{3x}}{2} = \frac{\pi }{3} - \frac{\pi }{4} + k2\pi \\\frac{{3x}}{2} = - \frac{\pi }{3} - \frac{\pi }{4} + k2\pi \end{array} \right.\)

\( \Leftrightarrow \left[ \begin{array}{l}\frac{{3x}}{2} = \frac{\pi }{{12}} + k2\pi \\\frac{{3x}}{2} = - \frac{{7\pi }}{{12}} + k2\pi \end{array} \right.\)\( \Leftrightarrow \left[ \begin{array}{l}x = \frac{\pi }{{18}} + k\frac{{4\pi }}{3}\\x = - \frac{{7\pi }}{{18}} + k\frac{{4\pi }}{3}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\).

Vậy phương trình đã cho có các nghiệm là \(x = \frac{\pi }{{18}} + k\frac{{4\pi }}{3}\) và \(x = - \frac{{7\pi }}{{18}} + k\frac{{4\pi }}{3}\) với k ∈ ℤ