Cho limits - 1^2 f( x )dx = 2, limits - 1^2 g( x )dx = - 1. Khi đó I = limits - 1^2 x + 2f( x ) - 3g( x ) dx bằng A. I = 17. B. I = 17/2 C. I = 15/2 D. I = 1/2
Cho \(\int\limits_{ - 1}^2 {f\left( x \right)dx} = 2,\) \(\int\limits_{ - 1}^2 {g\left( x \right)dx} = - 1\). Khi đó \(I = \int\limits_{ - 1}^2 {\left[ {x + 2f\left( x \right) - 3g\left( x \right)} \right]} dx\) bằng
A. \(I = 17.\)
B. \(I = \frac{{17}}{2}.\)
C. \(I = \frac{{15}}{2}.\)
D. \(I = \frac{1}{2}.\)