Tìm góc lượng giác $x$ sao cho:

cos 2x = cos (3x + 10°);

cos 2x = cos (3x + 10°)

$\Leftrightarrow \left[ \begin{array}{l}2x = 3x + 10^\circ + k360^\circ \\2x = - \left( {3x + 10^\circ } \right) + k360^\circ \end{array} \right.\left( {k \in \mathbb{Z}} \right)$

$\Leftrightarrow \left[ \begin{array}{l}x = - 10^\circ + k360^\circ \\x = - 2^\circ + k72^\circ \end{array} \right.\left( {k \in \mathbb{Z}} \right)$.