Tìm x biết: (8 – 5x)(x + 2) + 4(x – 2)(x + 1) + 2(x – 2)(x + 2) = 0.

(8 – 5x)(x + 2) + 4(x – 2)(x + 1) + 2(x – 2)(x + 2) = 0

⇔ –5x² – 2x + 16 + 4(x² – x – 2) + 2(x² – 4) = 0

⇔ –5x² – 2x + 16 + 4x² – 4x – 8 + 2x² – 8 = 0

⇔ x² – 6x = 0

⇔ x(x – 6) = 0

⇔ \(\left[ \begin{array}{l}x = 0\\x = 6\end{array} \right.\)

Vậy x = 0 hoặc x = 6.