Tìm x: (2x – 1)^2 – (x + 3)^2 = 0.
Tìm x: (2x – 1)2 – (x + 3)2 = 0.
Ta có:
(2x – 1)2 – (x + 3)2 = 0
⇔ (2x – 1 – x – 3)(2x – 1 + x + 3) = 0
⇔ (x – 4)(3x + 2) = 0
Vậy x = 4 hoặc .