Tìm lim\(\frac{{\sqrt {4{n^2} + 1} - \sqrt {n + 2} }}{{2n - 3}}\).

lim\(\frac{{\sqrt {4{n^2} + 1} - \sqrt {n + 2} }}{{2n - 3}}\)

= lim\(\frac{{\sqrt {4 + \frac{1}{{{n^2}}}} - \sqrt {\frac{1}{n} + \frac{2}{{{n^2}}}} }}{{2 - \frac{3}{n}}} = \frac{{\sqrt 4 }}{2} = \frac{2}{2} = 1\).