Gọi diện tích tam giác SBC là S₁.

\({S_{BMN}} = \frac{1}{2}d\left( {N,MB} \right).BM = \frac{1}{2}.\frac{2}{3}d\left( {C,SB} \right).\frac{1}{2}SB = \frac{1}{3}{S_1}.\)

\({V_1} = \frac{1}{3}.d\left( {P,\left( {SBC} \right)} \right).{S_{BMN}} = \frac{1}{3}.\frac{1}{3}d\left( {A,\left( {SBC} \right)} \right).\frac{1}{3}{S_1} = \frac{1}{9}{V_2}\).

Do đó \(\frac{{{V_1}}}{{{V_2}}} = \frac{1}{9}.\)