b) (2x – 1)(4x^2 + 2x + 1).
b) (2x – 1)(4x2 + 2x + 1).
b) (2x – 1)(4x2 + 2x + 1)
= (2x – 1)[(2x)2 + 2x.1 + 1]
= (2x)3 – 13
= 8x3 ‒ 1.