Tính các giới hạn sau: lim x suy ra - vô cùng ((2 + 4/3x) / (x^2 - 1)
Tính các giới hạn sau:
\(\mathop {\lim }\limits_{x \to - \infty } \frac{{2 + \frac{4}{{3x}}}}{{{x^2} - 1}}\);
\(\mathop {\lim }\limits_{x \to - \infty } \frac{{2 + \frac{4}{{3x}}}}{{{x^2} - 1}}\)\( = \mathop {\lim }\limits_{x \to - \infty } \frac{{\frac{2}{{{x^2}}} + \frac{4}{{3{x^3}}}}}{{1 - \frac{1}{{{x^2}}}}}\)\( = \frac{{\mathop {\lim }\limits_{x \to - \infty } \left( {\frac{2}{{{x^2}}} + \frac{4}{{3{x^3}}}} \right)}}{{\mathop {\lim }\limits_{x \to - \infty } \left( {1 - \frac{1}{{{x^2}}}} \right)}} = \frac{0}{1} = 0\).