Thực hiện các phép tính sau:

$\frac{{2{x^3}}}{{5{y^2}}}.\frac{{125{y^5}}}{{8x}}$;

$\frac{{2{x^3}}}{{5{y^2}}}.\frac{{125{y^5}}}{{8x}} = \frac{{2{x^3}.125{y^5}}}{{5{y^2}.8x}}$ $= \frac{{2{x^3}.5.25{y^5}}}{{5{y^2}.2.4x}} = \frac{{25{x^3}{y^5}}}{{4x{y^2}}} = \frac{{25{x^2}{y^3}}}{4}$.