b) 8x^3 + (x – y)^3;
b) 8x3 + (x – y)3;
b) 8x3 + (x – y)3
= (2x)3 + (x – y)3
= (2x + x ‒ y)[(2x)2 ‒ 2x(x ‒ y) + (x ‒ y)2]
= (3x ‒ y)(4x2 ‒ 2x2 + 2xy + x2 ‒ 2xy + y2)
= (3x ‒ y)[(4x2 ‒ 2x2 + x2) + (2xy ‒ 2xy) + y2]
= (3x ‒ y)(3x2 + y2).