Hoặc
c) x6 – 64
= (x3)2 ‒ 82
= (x3 + 8)(x3 ‒ 8)
= (x3 + 23)(x3 ‒ 23)
= (x + 2)(x2 ‒ 2x + 4)(x ‒ 2)(x2 + 2x + 4 ).