Gọi x, y lần lượt là số mol của alanin và axit glutamic có trong hỗn hợp X.

${\text{CH}}_3\text{CH}\left({\text{NH}}_2\right)\text{COOH}+\text{NaOH}\to {\text{CH}}_3\text{CH}\left({\text{NH}}_2\right)\text{COONa}+{\text{H}}_2\text{O}$

            x mol                   x mol               x mol                      x mol

$\text{HOOC}-{\text{CH}}_2{\text{CH}}_2\text{CH}\left({\text{NH}}_2\right)-\text{COOH}+2\text{NaOH}\to \text{NaOOC}-{\text{CH}}_2{\text{CH}}_2\text{CH}\left({\text{NH}}_2\right)-\text{COONa}+2{\text{H}}_2\text{O}$

                                y mol                          2y mol                              y mol                                   y mol

${\text{CH}}_3\text{CH}\left({\text{NH}}_2\right)\text{COOH}+\text{HCl}\to {\text{CH}}_3\text{CH}\left({\text{NH}}_3\text{Cl}\right)\text{COOH}$

            x mol                   x mol                   x mol

$\text{HOOC}-{\text{CH}}_2{\text{CH}}_2\text{CH}\left({\text{NH}}_2\right)-\text{COOH}+\text{HCl}\to \text{HOOC}-{\text{CH}}_2{\text{CH}}_2\text{CH}\left({\text{NH}}_3\text{Cl}\right)-\text{COOH}$

            y mol                                            y mol                                           y mol

Ta có: $\left\{\begin{array}{l}(x+2y)\cdot 22=30,8\\ (x+y)\cdot 36,5=36,5\end{array}\to \left\{\begin{array}{l}x=0,6\\ y=0,4\end{array}\right.\right.$