Lời giải

Đáp án đúng là: C

$A = \frac{{2x - 1}}{{6{x^2} - 6x}} - \frac{3}{{4{x^2} - 4}}$$= \frac{{2x - 1}}{{6x\left( {x - 1} \right)}} - \frac{3}{{4\left( {{x^2} - 1} \right)}}$

$= \frac{{2x - 1}}{{6x\left( {x - 1} \right)}} - \frac{3}{{4\left( {x - 1} \right)\left( {x + 1} \right)}}$$= \frac{{2\left( {2x - 1} \right)\left( {x + 1} \right) - 3.3x}}{{12x\left( {x - 1} \right)\left( {x + 1} \right)}}$

$= \frac{{2\left( {2{x^2} - x + 2x - 1} \right) - 9x}}{{12x\left( {x - 1} \right)\left( {x + 1} \right)}}$$= \frac{{2\left( {2{x^2} + x - 1} \right) - 9x}}{{12x\left( {x - 1} \right)\left( {x + 1} \right)}}$