Hoặc
A.S=20182019
Ta có:f(x)=ln2018xx+1⇒f'(x)=2018(x+1)22018xx+1=1x(x+1)=1x−1x+1
⇒f'(1)=11−12;f'(2)=12−13;...;f'(2018)=12018−12019
Nên:S=f'(1)+f'(2)+...+f'(2018)
=1−12+12−13+...+12018−12019=1−12019=20182019.
Chọn A.