Tính S(n)= 1 + (1+2)/2! + (1+2+3)/3! + ... + (1+2+3+..+n)/n! (n>0
Câu 23: Tính S(n)= 1 + (1+2)/2! + (1+2+3)/3! + ... + (1+2+3+..+n)/n! (n>0)
// Tính S(n)= 1 + (1+2)/2! + (1+2+3)/3! + ... + (1+2+3+..+n)/n! (n>0)
#include
using namespace std;
int Nhap()
{
int x;
do
{
cin >> x;
if (x < 0)
cout << "Nhap sai, yeu cau nhap lai!";
} while (x < 0);
return x;
}
double Tinh(int n)
{
float s = 0, t = 0;
long p = 1;
for (int i = 1; i <= n; i++)
{
t = t + i;
p = p * i;
s = s + (double)t / p;
}
return s;
}
int main()
{
int n;
cout << "Nhap so nguyen n: ";
n = Nhap();
cout << "Ket qua la: "<< Tinh(n) << endl;
return 0;
}