a) $\frac{1}{3}$ + $\frac{1}{3}$ + $\frac{1}{6}$

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b) $\frac{1}{12}$ + $\frac{3}{4}$ + $\frac{2}{12}$

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c) $\frac{19}{15}$ + 0 + $\frac{11}{15}$

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a) $\frac{1}{3}$ + $\frac{1}{3}$ + $\frac{1}{6}$

= $\frac{2}{6}$ + $\frac{2}{6}$+ $\frac{1}{6}$

= $\frac{5}{6}$

b) $\frac{1}{12}$ + $\frac{3}{4}$ + $\frac{2}{12}$

= $\frac{1}{12}$ + $\frac{9}{12}$ + $\frac{2}{12}$

= $\frac{12}{12}$

= 1

c) $\frac{19}{15}$ + 0 + $\frac{11}{15}$

= $\frac{19}{15}$ + $\frac{11}{15}$

= $\frac{30}{15}$

= 2