Tìm x biết: \({\left( {\frac{3}{4}} \right)^{3x - 1}} = \frac{{27}}{{64}}\).

\({\left( {\frac{3}{4}} \right)^{3x - 1}} = \frac{{27}}{{64}}\)

⇔ \({\left( {\frac{3}{4}} \right)^{3x - 1}} = {\left( {\frac{3}{4}} \right)^3}\)

⇔ 3x – 1 = 3

⇔ 3x = 4

⇔ x = \(\frac{4}{3}\)

Vậy x = \(\frac{4}{3}\).