Tìm lim 2n - căn (4n^2+n) / n + căn n^2-2n
Tìm lim2n−√4n2+nn+√n2−2n .
lim (2n−√4n2+n)=lim(2n−√4n2+n)(2n+√4n2+n)2n+√4n2+n=lim−n2n+√4n2+n
= lim−12+√4+1n=14
lim(n−√n2−2n)=lim(n−√n2−2n)(n+√n2−2n)n+√n2−2n=limn2−n2+2nn+√n2−2n
=lim21+√1−2n=1
Suy ra: lim2n−√4n2+nn+√n2−2n=−14 .