Thực hiện các phép tính sau: a) x^2+4x+4/ x^2-4+ x/ 2-x+ 4-x/ 5x-10;

Trả lời

a, $$\begin{gathered} \frac{x^2+4x+4}{x^2-4}+\frac{x}{2-x}+\frac{4-x}{5x-10} \\ =\frac{{(x+2)}^2}{(x+2)(x-2)}+\frac{-x}{x-2}+\frac{4-x}{5(x-2)} \\ =\frac{x+2}{x-2}+\frac{-x}{x-2}+\frac{4-x}{5(x-2)} \end{gathered}$$

$=\frac{5(x+2)-5x+4-x}{5(x-2)}=\frac{14-x}{5(x-2)}$