Cho hàm số bậc nhất f(x) = 3x + 2. Tính $f\left(1\right);f\left(0\right);f(-2);f\left(\frac{1}{2}\right);f\left(-\frac{2}{3}\right).$

• f(1) = 3 . 1 + 2 = 3 + 2 = 5;

• f(0) = 3 . 0 + 2 = 0 + 2 = 5;

• f(– 2) = 3 . (– 2) + 2 = – 6 + 2 = – 4;

• $f\left(\frac{1}{2}\right)=3.\frac{1}{2}+2=\frac{3}{2}+2=\frac{7}{2}$;

• $f\left(-\frac{2}{3}\right)=3.\left(-\frac{2}{3}\right)+2=-2+2=0$.