Hoặc
Ta có:
cosB^=AB2+BC2−AC22AB.BC⇔18=42+BC2−622.4.BC⇔BC=42+BC2−62
<=> BC2 − BC − 20 = 0
<=> (BC − 5)(BC + 4) = 0
⇒BC=5 (TM)BC=−4 (KTM)
Vậy BC = 5 cm.