Hoặc
c) x2−x+1x=x3+1x(x+1).
c) Ta có (x2 – x + 1) . x(x + 1) = x(x + 1)(x2 – x + 1) = x(x3 + 1);
Vì (x2 – x + 1) . x(x + 1) = x(x3 + 1) nên x2−x+1x=x3+1x(x+1).