Hoặc
b) y = log2(2x + 1) + 3−2x + 1.
b) y' = (log2(2x + 1))' + (3−2x + 1)'
=2x+1'2x+1ln2+132x−1'=22x+1ln2−32x−1'32x−12
=22x+1ln2−2x−1'⋅32x−1⋅ln332x−12
=22x+1ln2−2⋅ln332x−1=22x+1ln2−2ln3⋅3−2x+1.