Hoặc
b) 0,6x3 + x2z – 2,7xy2 + 0,4x3 + 1,7xy2.
b) 0,6x3 + x2z – 2,7xy2 + 0,4x3 + 1,7xy2
= (0,6x3 + 0,4x3) + x2z + (1,7xy2 – 2,7xy2)
= x3 + x2z – xy2.